-12x^2+24=-8x

Solution for -12x^2+24=-8x equation:

-12x^2+24=-8x

We move all terms to the left:

-12x^2+24-(-8x)=0

We get rid of parentheses

-12x^2+8x+24=0

a = -12; b = 8; c = +24;
Δ = b2-4ac
Δ = 82-4·(-12)·24
Δ = 1216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1216}=\sqrt{64*19}=\sqrt{64}*\sqrt{19}=8\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{19}}{2*-12}=\frac{-8-8\sqrt{19}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{19}}{2*-12}=\frac{-8+8\sqrt{19}}{-24}
$